## 5 Simple Math Problems No One Can Solve

Hard Math Problems #1 - Smart Math Problem Since this sum is n(n+1)/2, we need to solve the equation n(n+1)/2 = This is the quadratic equation n2+ n = 0. Solving for n, we obtain 11 as the answer and deduce that there were 12 people at the party. Sep 02,  · Mathematics is no doubt an exciting subject but not a cup of tea to everyone. It takes a lot of practice, memory power, and logical thinking to be a math champion. This quiz has some solid math questions that you may find tough to answer in one go. Well, do you think that you are brilliant at math? NP-hardness (non-deterministic polynomial-time hardness), in computational complexity theory, is the defining property of a class of problems that are, informally, "at least as hard as the hardest problems in NP". A simple example of an NP-hard problem is the subset sum problem.

## NP-hardness - Wikipedia

As they say, beggars can't be choosers, in fact begger take what they can get. A begger on the street can make one cigarette out of every 6 cigarette butts he finds. After one whole day of searching and checking public ashtrays the begger finds a total of 72 cigarette butts. How many cigarettes can he make and smoke from the butts he found? View Answer Discuss 14 If the begger can make a whole cigarette from 6 butts then he can make 12 cigarettes from the 72 he found. Once he smokes those, he then will have another 12 hard problems to solve, which gives him enough to make another 2 cigarettes.

A total of At a party, everyone shook hands with everybody else. There were 66 handshakes. How many people were at the party? Solving for n, we obtain 11 as the answer and deduce that there were 12 people at the party. Since 66 is a relatively small number, hard problems to solve, you can also solve this problem with a hand calculator. The last number that you entered 11 is n. I know a way by which i can make i can get total of by using five zeros 0,0,0,0,0 and any one mathematical operator.

Do you? View Answer Discuss 0! Can you find a seven digit number which describes itself. The first digit is the number of zeros in the number. The second digit is the number of ones in the number, etc. For example, hard problems to solve, in the numberthere are 2 zeros, 1 one, 2 twos, 0 threes and 0 fours. View Answer Discuss Solve it? My grandson is about as many days as my son in weeks, and my grandson is as many months as I am in years.

My grandson, my son and I together are years. Can you tell me my age in years? View Answer Discuss I am 72 years old.

Let m be my age in years. If s is my son's age in years, then my son is hard problems to solve weeks old. If g is my grandson's age in years, hard problems to solve, then my grandson is g days old.

The above system of 3 equations in 3 unknowns g, s and m can be solved as follows. So, I am 72 years old. Can you arrange four 9's and use of atmost 2 math symbolsmake the total be ? You can place weights on both side of weighing balance and you need to measure all weights between 1 and For example if you have weights 1 and 3,now you can measure 1,3 and 4 like earlier case, hard problems to solve, and also you can measure 2,by placing 3 on one side and 1 on the side which contain hard problems to solve substance to be weighed.

So question again is how many minimum weights and of what denominations you need to measure all weights from 1kg to kg. That is 1,3,9,27,81, and Using eight eights and addition only, can you make ? View Answer Discuss. I am 72 years old.

### Quiz: Very Hard Math Problems - ProProfs Quiz EQUATIONS CONTAINING ABSOLUTE VALUE(S) - Solve for x in the following equations. Solution Solution Solution Solution Solution. QUADRATIC EQUATIONS - Solve for x in the following equations. x Solution Solution Solution Solution Solution. EQUATIONS INVOLVING FRACTIONS - Solve for x in the following equations. Solution Solution. There is a two-digit number whose digits are the same, and has got the following property: When squared, it produces a four-digit number, whose first two digits are the same and equal to the original’s minus one, and whose last two digits are the same and equal to the half of the original’s. Sep 02,  · Mathematics is no doubt an exciting subject but not a cup of tea to everyone. It takes a lot of practice, memory power, and logical thinking to be a math champion. This quiz has some solid math questions that you may find tough to answer in one go. Well, do you think that you are brilliant at math?